An alternative approach would be to select using a IN condition on the where clause and group by column 1 and column 2. Then, using this as a sub-select group by the resultant column 1 and a count on column two. The matching identifiers are those with a count equal to the number of entries in the original IN condition.
Basically count how many of values each distinct key in column 1 matches and keep those keys where the count and the number of values match. David J. On Jun 18, 2011, at 17:51, Daron Ryan <daron.r...@gmail.com> wrote: > Hello, > > I need to search a table to find sets of rows that have a column matching > itself for the whole set and another column matching row for row with a list > I am going to supply. The result I should receive should be value of the > column that matches itself. > > For example given the following data in my table: > > 3; 1 > 3; 2 > 4; 8 > 4; 9 > 4; 10 > > I might need to search for 1,2. This should produce the result 3. Or if I > were to search for 8, 9, 10 the result should be 4. Searching for 8, 9 should > produce an empty result as should 8, 9, 10, 11. > > Can anyone recommend a strategy? > > -- > Sent via pgsql-general mailing list (pgsql-general@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-general -- Sent via pgsql-general mailing list (pgsql-general@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general
