Great, this does the trick thanks!!

um... somevalue+random() is a simplified version of what I really wanted to
do, i just wante the general idea of what the  query would look like.




2008/1/21, Andrei Kovalevski <[EMAIL PROTECTED]>:
>
> May be this is what you need:
>
> select
>   test.uid, coalesce(t.somevalue + a.max + t.uid, test.somevalue)
> from
>   test
>     left outer join
>   (select
>       *
>     from
>       test
>     where
>       (uid, somevalue) not in
>       (select min(uid), somevalue from test group by somevalue)
>   ) t on (test.uid = t.uid),
>   (select max(somevalue) from test) a
>
> Rhys Stewart wrote:
> > ok, let me clarify, dont want to remove them just want them changed
> > but need to keep the uid. However, I would like just one somevalue to
> > remain the same. so for example, uids, 2,4 and 8 have somevalue 44,
> > after i would like 2 to remain 44 but uids 4 and 8 would be changed.
> > 2008/1/21, Jeff Davis <[EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]>>:
> >
> >     On Mon, 2008-01-21 at 12:36 -0500, Rhys Stewart wrote:
> >     > Hi list,
> >     >
> >     > have the following table
> >     >
> >     > uid|somevalue
> >     > --------------------
> >     > 1|11
> >     > 2|44
> >     > 3|31
> >     > 4|44
> >     > 5|71
> >     > 6|33
> >     > 7|33
> >     > 8|44
> >     > 9|14
> >     >
> >     > would like to remove the duplicate values in the column somevalue.
> >     > doing this by just adding a random number  is perfectly fine,
> >     however
> >     > i want to retain at least one of the original values of
> >     somevalue. Any
> >     > ideas how to do this in in a query?
> >
> >     Would something like this help?
> >
> >     SELECT MIN(uid), somevalue FROM mytable GROUP BY somevalue;
> >
> >     Also consider just doing:
> >
> >     SELECT DISTINCT somevalue FROM mytable;
> >
> >     ...if you don't need uid in the result set.
> >
> >     Regards,
> >             Jeff Davis
> >
> >
>
>
> --
> Andrei Kovalevski
> PostgreSQL Replication, Consulting, Custom Development, 24x7 support
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>
>

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