I apologize, that was sloppy.
I was using the acldefault() function with pg_roles, like this:
=> select rolname,  acldefault('f',oid) from pg_roles where rolname like 'mjt%' 
order by 1;
  rolname  |              acldefault
-----------+--------------------------------------
mjt_test1 | {=X/mjt_test1,mjt_test1=X/mjt_test1}
mjt_test2 | {=X/mjt_test2,mjt_test2=X/mjt_test2}
(2 rows)

I had issued
alter default privileges for role mjt_test1 revoke execute on functions from 
public;
but had not done a similar ALTER for mjt_test2. And so I was surprised that 
they both showed a default =X/rolename.

Examining  \ddp and its underlying quuery, I see that view column 
pg_default_acl gets a new row with defaclacl populated after the ALTER DEFAULT 
PRIVILEGES.

Thanks very much for your guidance, I am on track now.

Mike Tefft

From: Tom Lane <t...@sss.pgh.pa.us>
Sent: Friday, July 5, 2024 2:22 PM
To: Tefft, Michael J <michael.j.te...@snapon.com>
Cc: pgsql-general@lists.postgresql.org
Subject: Re: Removing the default grant of EXECUTE on functions/procedures to 
PUBLIC

"Tefft, Michael J" <Michael. J. Tefft@ snapon. com> writes: > I was checking 
pg_roles. acl_default to see if my role-level ALTER DEFAULT PRIVILEGES had been 
effective. But I see the same content both before and after the ALTEr. Er, what?


"Tefft, Michael J" 
<michael.j.te...@snapon.com<mailto:michael.j.te...@snapon.com>> writes:

> I was checking pg_roles.acl_default to see if my role-level ALTER DEFAULT 
> PRIVILEGES had been effective. But I see the same content both before and 
> after the ALTEr.



Er, what?  There's no column named acl_default in pg_roles, nor any

other standard PG view.



psql's "\ddp" command is the most usual way to examine current

defaults:



regression=# create user joe;

CREATE ROLE

regression=# ALTER DEFAULT PRIVILEGES FOR USER joe REVOKE EXECUTE ON FUNCTIONS 
FROM public;

ALTER DEFAULT PRIVILEGES

regression=# \ddp

           Default access privileges

 Owner | Schema |   Type   | Access privileges

-------+--------+----------+-------------------

 joe   |        | function | joe=X/joe

(1 row)



                                       regards, tom lane

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