Hi,
Am 06.01.22 um 13:36 schrieb Andreas Joseph Krogh:
På torsdag 06. januar 2022 kl. 13:31:19, skrev Thomas Markus
<t.mar...@proventis.net>:
Hi,
Am 06.01.22 um 13:28 schrieb Andreas Joseph Krogh:
Hi, in PG-14 this query returns "value" (with double-quotes):
SELECT ('{"key":"value"}'::jsonb)['key'];
┌─────────┐
│ jsonb │
├─────────┤
│ "value" │
└─────────┘
(1 row)
and this returns 'value' (without the quotes):
SELECT ('{"key":"value"}'::jsonb)->> 'key';
┌──────────┐
│ ?column? │
├──────────┤
│ value │
└──────────┘
(1 row)
How to I use the subscript syntax and get the result as varchar
instead of JSONB, assuming I /know/ the JSON-field is a String?
simply cast your value
SELECT (('{"key":"value"}'::jsonb)->> 'key')::text;
best regards
Thoma
I think you misread my message. What I want is for the subscript-version:
('{"key":"value"}'::jsonb)['key']
to return:
┌──────────┐
│ ?column? │
├──────────┤
│ value │
└──────────┘
instead of
┌─────────┐
│ jsonb │
├─────────┤
│ "value" │
└─────────┘
yeah right :(
complicated but this should do:
SELECT jsonb_build_array( ('{"key":"value"}'::jsonb)['key'] ) ->> 0;
--
*Andreas Joseph Krogh*
CTO / Partner - Visena AS
Mobile: +47 909 56 963
andr...@visena.com
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