Regular expressions, in my opinion, can be a very powerful text search and replace engine if you know how to use it.Feel free to enhance what I provided below; it seems to work for the example you provided. postgres=# select regexp_replace(substring('Class V,Class VI,Class VII,Competitive Exam,Class VIII,Class X,Class XI,Class IX,Class XII',1,60),'(.*),\w+','\1'); regexp_replace -------------------------------------------------------- Class V,Class VI,Class VII,Competitive Exam,Class VIII(1 row)
Regards, PflugerGeek On Saturday, May 16, 2020, 10:19:28 AM CDT, Alex Magnum <magnum11...@gmail.com> wrote: Hi, I have a string that I want to cut to 60 char and then remove the last field and comma. substring('Class V,Class VI,Class VII,Competitive Exam,Class VIII,Class X,Class XI,Class IX,Class XII',1,60); substring | Class V,Class VI,Class VII,Competitive Exam,Class VIII,Class Now I try to remove the last field and comma ",Class" To get Class V,Class VI,Class VII,Competitive Exam,Class VIII Is there a function or easy way to do this?Any help would be appreciated. Thank youAlex