Regular expressions, in my opinion, can be a very powerful text search and 
replace engine if you know how to use it.Feel free to enhance what I provided 
below; it seems to work for the example you provided.
postgres=# select regexp_replace(substring('Class V,Class VI,Class 
VII,Competitive Exam,Class VIII,Class X,Class XI,Class IX,Class 
XII',1,60),'(.*),\w+','\1');                     regexp_replace                 
    -------------------------------------------------------- Class V,Class 
VI,Class VII,Competitive Exam,Class VIII(1 row)



Regards,

PflugerGeek
    On Saturday, May 16, 2020, 10:19:28 AM CDT, Alex Magnum 
<magnum11...@gmail.com> wrote:  
 
 Hi,
I have a string that I want to cut to 60 char and then remove the last field 
and comma.

substring('Class V,Class VI,Class VII,Competitive Exam,Class VIII,Class X,Class 
XI,Class IX,Class XII',1,60);

substring | Class V,Class VI,Class VII,Competitive Exam,Class VIII,Class

Now I try to remove the last  field and comma  ",Class"
To get Class V,Class VI,Class VII,Competitive Exam,Class VIII
Is there a function or easy way to do this?Any help would be appreciated.
Thank youAlex  

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