Alexander Farber wrote:
> Here is such a query for the best player
>
> # SELECT AVG(score) FROM words_moves WHERE uid = 1201;
> avg
> ---------------------
> 18.4803525523319868
>
> However I am not sure, how to "marry" the 2 queries?
>
> I have tried to add words_moves through another JOIN, but that does not
> work:
You may use a correlated subquery in the SELECT clause,
like this:
SELECT
u.elo,
u.uid,
(SELECT AVG(score) FROM words_moves WHERE uid=u.uid),
s.given,
s.photo
Best regards,
--
Daniel Vérité
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Twitter: @DanielVerite
