On 01.11.2010 15:31, Heikki Linnakangas wrote:
This used to work in the PostgreSQL 8.4 ecpg preprocessor:
EXEC SQL EXECUTE mystmt USING 1.23;
but in 9.0 it throws an error:
floattest.pgc:39: ERROR: variable "1" is not declared
Attached is the full test case, drop it in
src/interfaces/ecpg/test/preproc and compile.
I bisected the cause to this commit:
commit b2bddc2ff22f0c3d54671e43c67a2563deed7908
Author: Michael Meskes <mes...@postgresql.org>
Date: Thu Apr 1 08:41:01 2010 +0000
Applied Zoltan's patch to make ecpg spit out warnings if a local
variable hides a global one with the same name.
I don't immediately see why that's causing it, but it doesn't seem
intentional.
On closer look, it's quite obvious: the code added to ECPGdump_a_type
thinks that ECPGt_const is a variable type, and tries to look up the
variable. The straightforward fix is this:
diff --git a/src/interfaces/ecpg/preproc/type.c
b/src/interfaces/ecpg/preproc/type.c
index cc668a2..a53018b 100644
--- a/src/interfaces/ecpg/preproc/type.c
+++ b/src/interfaces/ecpg/preproc/type.c
@@ -246,7 +246,7 @@ ECPGdump_a_type(FILE *o, const char *name, struct
ECPGtype * type,
struct variable *var;
if (type->type != ECPGt_descriptor && type->type != ECPGt_sqlda &&
- type->type != ECPGt_char_variable &&
+ type->type != ECPGt_char_variable && type->type != ECPGt_const
&&
brace_level >= 0)
{
char *str;
But I wonder if there is a better way to identify variable-kind of
ECPGttypes than list the ones that are not. There's some special
ECPGttypes still missing from the above if-test, like
ECPGt_NO_INDICATOR, but I'm not sure if they can ever be passed to
ECPGdump_a_type. Seems a bit fragile anyway.
--
Heikki Linnakangas
EnterpriseDB http://www.enterprisedb.com
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