The following bug has been logged online:
Bug reference: 1807
Logged by: Janet Hempstead
Email address: [EMAIL PROTECTED]
PostgreSQL version: 8.0.3
Operating system: Solaris 9 (sparc)
Description: cannot build postgresql: libascii_and_mic.so.0.0: No
such file or directory
Details:
I am trying to build postgresql 8.0.3 on a Sun Ultra 5 running Solaris 9. I
have the Sunfreeware (small) version of gcc 3.3.2 installed. I have
searched and I cannot find a similar problem report and I have been unable
to resolve this compile problem (although I think it is in the order that
things are specified on the gcc line).
I cannot add -m64 to the compile line because there
are other Sunfreeware packages installed that are not 64-bit-enabled (I
think it was readline): is this *really* the problem?
Here is my ./configure invocation:
export LDFLAGS='-L /usr/lib -L /usr/local/lib -L /usr/local/ssl/lib'
export CPPFLAGS='-fPIC -I /usr/include -I /usr/local/include -I
/usr/local/ssl/include'
export CFLAGS='-fPIC -I /usr/include -I /usr/local/include -I
/usr/local/ssl/include'
export CXXFLAGS=$CFLAGS
export LDFLAGS_SL=''
./configure \
--with-openssl \
--with-pam \
--with-perl \
--enable-thread-safety \
--disable-nls
Here is the context of the error message:
-Wmissing-prototypes -Wpointer-arith -Wendif-labels -fno-strict-aliasing
-fPIC -I../../../../../../src/include -fPIC -I /usr/include -I
/usr/local/include -I /usr/local/ssl/include -c -o ascii_and_mic.o
ascii_and_mic.c
gcc -shared -h libascii_and_mic.so.0 ascii_and_mic.o
-L../../../../../../src/port -L -L -L -o libascii_and_mic.so.0.0
gcc: libascii_and_mic.so.0.0: No such file or directory
make[3]: *** [libascii_and_mic.so.0.0] Error 1
make[3]: Leaving directory
`/lib001/postgresql-8.0.3/src/backend/utils/mb/conversion_procs/ascii_and_mi
c'
make[2]: *** [all] Error 2
make[2]: Leaving directory
`/lib001/postgresql-8.0.3/src/backend/utils/mb/conversion_procs'
make[1]: *** [all] Error 2
make[1]: Leaving directory `/lib001/postgresql-8.0.3/src'
make: *** [all] Error 2
I am probably doing something really stupid; please let me know. Thanks!
Janet
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