This doesn't seem right:

CREATE VIEW inci AS
SELECT date, inci_id, protocol, a.ip_addr, b.ip_addr, spt, dpt
FROM      (SELECT addr_id, ip_addr FROM addrs) AS a
     JOIN incident ON incident.source_addr_id = a.addr_id 
     JOIN (SELECT addr_id, ip_addr FROM addrs) 
           AS b ON incident.destination_addr_id = b.addr_id
     JOIN protocols USING( protocol_id );

Produces: ERROR:  column "ip_addr" duplicated

Yet the select on it's own works just fine...  I've attached the database
definition.

                                                 version                        
                        
-------------------------------------------------------------------------------
--------------------------
 PostgreSQL 8.0.2 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 3.3.2
(Mandrake Linux 10.0 3.3.2-6mdk)


Thanks,
Rob

-- 
 12:31:42 up 24 days, 14:10,  6 users,  load average: 3.08, 2.63, 2.63
Linux 2.6.5-02 #8 SMP Mon Jul 12 21:34:44 MDT 2004

Attachment: test.sql
Description: Binary data

Attachment: pgplqDYerWTQO.pgp
Description: PGP signature

Reply via email to