I am unable to cast the output of timeofday() to a timestamp under postgresql 7.3.3-1 under cygwin. I can do so under 7.3.2 running on Linux.
All the best,
Tim
Results as follows:
________________________________________________________________________________ Cygwin - Postgresql 7.3.3 - Windows 2000: ________________________________________________________________________________
version
-----------------------------------------------------------------------------------------
PostgreSQL 7.3.3 on i686-pc-cygwin, compiled by GCC gcc (GCC) 3.2 20020927 (prerelease)
# select timeofday();
timeofday --------------------------------------- Fri Jul 25 11:14:50.406227 2003 GMTDT
# select timeofday()::timestamp;
ERROR: Bad timestamp external representation 'Fri Jul 25 11:15:23.629227 2003 GMTDT'
________________________________________________________________________________ Redhat Linux 9, Postgresql 7.3.2 ________________________________________________________________________________
version -----------------------------------------------------------------------------------------------------------------------------------
PostgreSQL 7.3.2 on i386-redhat-linux-gnu, compiled by GCC i386-redhat-linux-gcc (GCC) 3.2.2 20030213 (Red Hat Linux 8.0 3.2.2-1)
# select timeofday();
timeofday
-------------------------------------
Fri Jul 25 11:05:23.371428 2003 IST# select timeofday()::timestamp;
timeofday
----------------------------
2003-07-25 11:05:45.440165---------------------------(end of broadcast)--------------------------- TIP 7: don't forget to increase your free space map settings
