Hi Satish, Exactly. Something went wrong when I pull the remote content last week. I made a clean download of dev version and the problem is solved.
Thanks, Danyang On 2023-05-07, 7:14 AM, "Satish Balay" <[email protected] <mailto:[email protected]>> wrote: Perhaps you are not using the latest 'main' (or release) branch? I get (with current main): $ mpiexec -n 4 ./petsc_fppflags compiled by STANDARD_FORTRAN compiler called by rank 0 called by rank 1 called by rank 2 called by rank 3 There was a issue with early petsc-3.19 release - here one had to reorder the lines from: FPPFLAGS = include ${PETSC_DIR}/lib/petsc/conf/variables include ${PETSC_DIR}/lib/petsc/conf/rules to include ${PETSC_DIR}/lib/petsc/conf/variables include ${PETSC_DIR}/lib/petsc/conf/rules FPPFLAGS = But this is fixed in latest release and main branches. Satish On Sun, 7 May 2023, Danyang Su wrote: > Hi Satish, > > Sorry, this is a typo when copy to the email. I use FPPFLAGS in the makefile. > Not sure why this occurs. > > Actually not only the preprocessor fails, the petsc initialize does not work > either. Attached is a very simple fortran code and below is the test results. > Looks like the petsc is not properly installed. I am working on macOS > Monterey version 12.5 (Intel Xeon W processor). > > Compiled using petsc-3.18 > (base) ➜ petsc-dev-fppflags mpiexec -n 4 ./petsc_fppflags > compiled by STANDARD_FORTRAN compiler > called by rank 0 > called by rank 1 > called by rank 2 > called by rank 3 > > compiled using petsc-dev > (base) ➜ petsc-dev-fppflags mpiexec -n 4 ./petsc_fppflags > called by rank 2 > called by rank 2 > called by rank 2 > called by rank 2 > > Thanks, > > Danyang > > On 2023-05-06, 10:22 PM, "Satish Balay" <[email protected] > <mailto:[email protected]> <mailto:[email protected] > <mailto:[email protected]>>> wrote: > > > On Sat, 6 May 2023, Danyang Su wrote: > > > > Hi All, > > > > > > > > My code has some FPP. It works fine in PETSc 3.18 and earlier version, but > > stops working in the latest PETSc-Dev. For example the following FPP > > STANDARD_FORTRAN is not recognized. > > > > > > > > #ifdef STANDARD_FORTRAN > > > > 1 format(15x,1000a15) > > > > 2 format(1pe15.6e3,1000(1pe15.6e3)) > > > > #else > > > > 1 format(15x,<ncol>a15) > > > > 2 format(1pe15.6e3,<ncol>(1pe15.6e3)) > > > > #endif > > > > > > > > In the makefile, I define the preprocessor as PPFLAGS. > > > > > > > > PPFLAGS := -DLINUX -DRELEASE -DRELEASE_X64 -DSTANDARD_FORTRAN > > > Shouldn't this be FPPFLAGS? > > > > > Can you send us a simple test case [with the makefile] that we can try to > demonstrate this problem? > > > Satish > > > > > > … > > > > exe: $(OBJS) chkopts > > > > -${FLINKER} $(FFLAGS) $(FPPFLAGS) $(CPPFLAGS) -o $(EXENAME) $(OBJS) > > ${PETSC_LIB} ${LIS_LIB} ${DLIB} ${SLIB} > > > > > > > > Any idea on this problem? > > > > > > > > All the best, > > > > > > > > > > > > > > > >
