Hi,
we had the discussion a few times on how to match against a grammar, for
example here: http://irclog.perlgeek.de/parrot/2008-05-31#i_322490
Attached patch adds the $string ~~ Grammar.new form to S05, on which
@Larry.pick($some) seems to have agreed upon.
In the end I don't really care how it's done, I just want it to be
specced ;-)
Moritz
--
Moritz Lenz
http://moritz.faui2k3.org/ | http://perl-6.de/
--- Rule.pod.old 2008-09-08 17:27:42.000000000 +0200
+++ Rule.pod 2008-09-08 17:32:15.000000000 +0200
@@ -3586,8 +3586,6 @@
$parsetree = m:keepall/<Perl.prog>/;
}
-=back
-
=item *
To switch to a different grammar in the middle of a regex, you may use the C<:lang> adverb.
@@ -3595,6 +3593,14 @@
token funnylang { '{' [ :lang($funnylang.unbalanced('}')) <expr> ] '}' }
+=item *
+
+To match against the C<TOP> rule of a grammar, you instantiate the grammar:
+
+ $string ~~ Identity.new;
+
+=back
+
=head1 Syntactic categories
For writing your own backslash and assertion subrules or macros, you may
