Let's say that I want $expression?;
to mean the same thing as the statement $_ = $expression; That is, any statement that ends with a '?;' instead of a ';' evaluates in scalar context instead of void context and stores the result as the topic '$_'. (I was going to suggest '?' intead of '?;', but a quick review of the specs pointed out that this would be ambiguous wrt the ? prefix operator.) Is perl 6 powerful enough to enable this sort of thing with its existing tools, or would the parser need to be altered? -- Jonathan "Dataweaver" Lang
