Hi all, Apologies if this has been covered. What should this do?
($x,$y) := ($y,$x); In Perl5: $x=2; $y=3; print "x: $x y: $y\n"; (*::x, *::y) = (*::y, *::x); $y=4; print "x: $x y: $y\n"; $x=5; print "x: $x y: $y\n"; This program shows typeglob aliasing. If we try to alias swapped value, we merely swap what they are pointing at and we haven't aliased anything. I am not sure this should be appropriate behavior for Perl6. Aliasing will be much more common in Perl6 so this will be a trap for many. In fact, consider this: ($c, $d) := ($y, $x); # later ($x,$y) := ($c, $d); # whoops! That's going to confuse the heck out of people. If we do as Perl5 does, we'll merely be swapping values since aliasing really doesn't make much sense here, but that means for this case, ":=" == "=". Cheers, Ovid -- If this message is a response to a question on a mailing list, please send follow up questions to the list. Web Programming with Perl -- http://users.easystreet.com/ovid/cgi_course/
