On Thursday 08 July 2004 05:25, Larry Wall wrote: > : say @x[rand]; # how about now? > > Well, that's always going to ask for @x[0], which isn't a problem. > However, if you say rand(@x), it has to calculate the number of > elements in @x, which could take a little while... I'd expect to be rand(@x) = rand(1)[EMAIL PROTECTED] = rand(1)*Inf = Inf or NaN.
Case 1 (Inf) would give Inf (which can be argued, since infinite many more elements are bigger than any given finite number), and case 2 could give an exception ... Regards, Phil
