Scott Bronson skribis 2004-07-01 13:31 (-0700): > > Then invent a horizontal ; operator that does not :) > > > pray_to $_ then sacrifice <$virgin> for @evil_gods > > pray_to $_ ., then sacrifice <$virgin> for @evil_gods; > Sure. But what is .,? C<then> could work alone, couldn't it?
It is a horizontal ;. See: ., If you turn your head 90 degrees counter clockwise, you see the horizontal semicolon and even a smiley face :) Juerd
