On Sat, Dec 13, 2003 at 12:12:59PM -0800, Larry Wall wrote: > > print $ref > > it doesn't do what you want, but > > print $ref.as(Array) > > might work a lot better, though of course > > print @$ref >
What is supposed to do the splat operator in this context? My understanding is that when an operator expects something and gets a ref instead, the ref is dereferenced until the expected operand is found. The interpretor barks otherwise. So I expect print *$ref when $ref is ref to an array to be equivalent to print [EMAIL PROTECTED] which in turn should behave like print @$ref because C<print> splats its operands. I don't pretend that C<print *$ref> is very readable, I just ask what it does or if it is at all permitted. -- stef
