Luke Palmer wrote: >>> From: "Joe Gottman" <[EMAIL PROTECTED]> >>> Date: Fri, 3 Jan 2003 22:25:16 -0500 >>> >>> "JG" == Joe Gottman <[EMAIL PROTECTED]> writes: >>> >>> JG> Speaking of which, is there a run-time test to check if a variable >>> JG> is of >>> JG> integral type? Something like >>> JG> print "date" if ($var is int) && (1 <= $var <= 31); >>> >>> the old standby is: >>> >>> int( $var ) == $var >> >> I'm not sure if this works. >> >> my $var = "0"; # Notice the quotation marks >> print "is integer" if (int($var) == $var); >> >> In the above case int($var) == $var returns true when I would want it to >> return false.
Why? It returns true in perl5; 0 certainly is an integer value. > print "date" if $var.isa(int); > print "date" if isa $var: int; > print "date" if $var ~~ int; > > Those should all work. IMO the first reads the best. That will also > work for C<Int>s, as C<Int> is a subclass of C<int> (I think). These only determine if $var is of type int or Int. However: my $var = 0; # or my $var = "0"; # or my int $var = 0; # or my num $var = 0; # all 4 cases should print "is integer" print "is integer" if int $var == $var; This should work as a more generic method to test Integer *value*, rather than type, which IMHO is more useful (and more commonly wanted). This message was sent using the Webmail System hosted by OARDC Computing Services -- http://webmail.oardc.ohio-state.edu:8080
