On Sun, Dec 16, 2001 at 03:55:10PM +1100, Damian Conway wrote:
[...]
> > And, just for laughs:
> >
> > $ref = [1,2];
> > @ary[$ref] = foo(); # probably a syntax error
Ok, as far as I can recall, Larry hinted that arrays and references to
arrays would be interchangable in many contexts in P6. In this case, I
can't see any reason that subscripting would *want* to do a SvIV on
a known reference, so I would expect it to obey that logic and treat
the reference as an array. Thus, I expect this to be list context for
the exact same reason that:
@bar = (1,2);
@ary[@bar] = foo();
would be.
Next question, though:
$val = (foo())[0];
List?
--
Aaron Sherman
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