On Wed, Oct 10, 2001 at 04:04:18PM -0500, Jonathan Scott Duff wrote:
> On Wed, Oct 10, 2001 at 01:27:35PM -0700, Colin Meyer wrote:
> >
> > Does this mean that
> >
> > @a ^+= @b;
> >
> > will add every value of @b to every value of @a?
>
> That's what I'd expect it to do. Well ... that's assuming you really
> mean "each" where you said "every". i.e.,
>
> my $i = 0;
> while ($i < length(@a) && $i < length(@b)) {
> @a[$i] += @b[$i];
$i++;
> }
What I'd expect is more like:
foreach my $elem (@a) {
$elem ^+= @b;
}
Have fun,
-C.
