Hello!
Is this going to concat $a,$b and $c?
$foo = _($a,$b,$c);
(One way to save underlines and spaces.)
Or would that be:
$foo = _@($a,$b,$c);
BTW: what will these do?
$a _=_ ($b,$c);
$a ^_= ($b,$c); # (better with hypo-operator?, see below)
(WIM in Perl 5: $a .= $b.$c ?)
Could there also be *hypo*-operators, i.e. operators which try to
*lower* (reduce) the dimensionality of their operands to the lowest
common dim. So
$foo = 5 +^ (1,2);
would set $foo to (5 + 1) + 2 and
$foo = $a _^ ($b,$c);
$a _=^ ($b,$c);
would do the same concats as above respectively?
Another application:
$sum = 0 +^ @values;
Granted: ^ is not the best choice for a meta-operator which lowers
something. :)
-Edwin
