At 10:23 PM 5/8/2001 +0100, Simon Cozens wrote:
>On Tue, May 08, 2001 at 05:08:58PM -0400, Dan Sugalski wrote:
> > @foo = ({scalar each %some_tied_hash});
> >
> > with the function being called only when you access a particular element?
>
>I'm still confused. Firstly, this doesn't involve first-order blocks, which
>was kinda what the entire question was about.
Well, it's a block in list context, which is what I was shooting for.
>Secondly, it isn't clear what it
>means. "scalar each" in Perl5-think means "return the first element". (Try:
>perl -le '%a=(a=>"b", c=>"d"); print while $_ = scalar each %a')
Odd.
%foo = (a => 1, b=>2);
while ($_ = scalar each %foo) {
print $_, "\n";
}
does the expected thing. (printing a and b) Which is what I was shooting for.
>Is this not
>merely @foo=(keys %some_tied_hash), which should call the tied functions in
>the same way? Not a convincing example, I'm afraid.
Well, we currently don't call the tied function that way. But yes. (And the
example was supposed to be illustrative, not convinving)
Dan
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Dan Sugalski even samurai
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