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Organization: a) Discordia b) none c) what's that?
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Date: Tue, 22 Aug 2000 13:48:36 EDT
From: Jerrad Pierce <belg4mit>
> $n = pop fn()
>you are just obfuscating writing
>
> $n = (fn())[-1];
yes
>It should not be done because it is wrong to lose compile-time
>type checking save under grave environmental stress, the likes
Why are you losing checking? It would seem right now keys
would first check to make sure it'll be getting *something* OR die
then to make sure that that something is a hash OR die
And all I said was replace the last OR die with:
OR warn (if under strict&|-w) AND cast at run-time
If you gave it hash you short-circuit right out and have not lost any time.
If it in fact is not a hash, you may get warning under strict or -w.
>of which you are yet to demonstrate. The burden of proof rests
>with you to show why to turn perl dumber.
This is *not* making it dumber, the only way it would make it dumber is if
you lost your test. But you don't have to lose your compile-time test...
>But that comes with similar attendant problems. What then
>should
> while ( ($k,$v) = each fn() ) {}
>do? How often should fn() be called there? And what if it
>returns a hash ref versus a list? What about a list of one
>hash ref?
It should be called once, otherwise you would loop indefinitely.
It should then pass every other value into $k and $v, while you iterate
over the contents. For example:
while ( ($k,$v) = each fn() ){
push @F, $k;
push @G, $v;
}
not being dissimilar from
@F = fn();
unzip(2, \@F)
>Comflating values with variables is not always sensible: consider
>4++, for example; this isn't (old) FORTRAN. :-)
Well that's a different issue, since that always evaluates to the same thing...
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