On Wed, 16 Aug 2000, Glenn Linderman wrote: > > What should happen when the expression given to C<pop()>, or > > C<shift()> evaluates to a negative number? I see three options: [...] > > > > 3) C<pop()> would then act as C<shift()> and C<shift()> would > > act as C<pop()> > > > I like #3 too, does that make a better consensus? Can you guess which option I favor? :> Dave
- RFC 56 (v2) Optional 2nd argument to C<pop()> an... Perl6 RFC Librarian
- Re: RFC 56 (v2) Optional 2nd argument to C<pop... Glenn Linderman
- Dave Storrs