>>>>> "PRL" == Perl6 RFC Librarian <[EMAIL PROTECTED]> writes:
PRL> in a program. However, the following is self-documenting:
PRL> $check = ^cylinder_vol == ^radius**2 * ^height
PRL> or die ^last_words;
PRL> This uses the I<named placeholder> notation. If two placeholders use the
PRL> same identifier, they refer to the same argument. Therefore, the following
PRL> is equivalent to the previous line:
PRL> $check = ^cylinder_vol == ^radius*^radius * ^height
PRL> or die ^last_words;
where is pi in that equation? :-)
how are the real params assigned to the named placeholders? in order of
appearance in that expression?
PRL> First the positional placeholders are filled in (a higher numbered
PRL> positional placeholder than the number of parameters results in a
PRL> compile-time error). The anonymous and named placeholders fill in the
PRL> missing places in the order in which they appear, from left to right.
well you answer that here but it should be mentioned above as well.
uri
--
Uri Guttman --------- [EMAIL PROTECTED] ---------- http://www.sysarch.com
SYStems ARCHitecture, Software Engineering, Perl, Internet, UNIX Consulting
The Perl Books Page ----------- http://www.sysarch.com/cgi-bin/perl_books
The Best Search Engine on the Net ---------- http://www.northernlight.com
