Re: [perl #127339] problem using Duration

[mt1957]

On 01/22/2016 01:52 PM, Sam S. via RT wrote:
This is the root of the problem:
   ➜ say ($d + 2).WHAT;
   (Duration)
   
   ➜ say ($d * 2).WHAT'
   (Num)

The behavior of += and *= is just a consequence of that.
Then the question remains why the multiplication results in Num if it 
multiplies with an integer. Besides, addition of a Num still becomes a 
Duration. See following REPL;

> my Duration $d .= new(10);
10
> $d += 1.1
11.1
> $d += 1.1
12.2
> $d.WHAT.say
(Duration)