On Jun 19, 2013, at 12:34 PM, Philippe de Rochambeau (via RT) <perl6-bugs-follo...@perl.org> wrote: > # New Ticket Created by Philippe de Rochambeau > # Please include the string: [perl #118541] > # in the subject line of all future correspondence about this issue. > # <URL: https://rt.perl.org:443/rt3/Ticket/Display.html?id=118541 > > > > > Hello, > > according to http://en.wikibooks.org/wiki/Perl_6_Programming/Types_and_Context > > the following statement is supposed to set $z to 3 > > my $z = $(2..4); # Three elements, becomes the number 3 > > In Rakudo Perl 2013.5 on Windows 7, 2..4 is returned instead > > perl6 -e "my $z = $(2..4); say $z" > 2..4
The $() provides item context to the range. As much as the my $z = does. So in effect, this is really the same as: my $z = 2..4 And that is a range, as observable here: $perl6 -e 'my $z = 2..4; say $z.WHAT' (Range) I think the example: my $z = $(2..4); # Three elements, becomes the number 3 is incorrect. If you really would like to see the number of elements, use the .elems method: $ perl6 -e 'my $z = (2..4).elems; say $z' 3 Hope this helps. Liz
