[perl #61602] Fix Integral values of Inf/NaN

[Will Coleda via RT]

On Mon Dec 22 06:00:30 2008, cspencer wrote:
> 
> When calling the .int method on Inf/Nan, the reported value is 
incorrect:
> 
>    "Inf.int.say" produces "-2147483648"
> 
> and
> 
>    "NaN.int.say" produces "-2147483648"


I think the method for this is now ".Int", but the answers aren't 
righter:

19:12 < [Coke]> rakudo: say Inf.Int;
19:12 <+p6eval> rakudo ebd4d8: OUTPUT«-9223372036854775808␤»
19:13 < [Coke]> rakudo: say NaN.Int
19:13 <+p6eval> rakudo ebd4d8: OUTPUT«-9223372036854775808␤»


-- 
Will "Coke" Coleda