# New Ticket Created by Stephane Payrard
# Please include the string: [perl #76596]
# in the subject line of all future correspondence about this issue.
# <URL: http://rt.perl.org/rt3/Ticket/Display.html?id=76596 >
15:48:09] <cognominal> rakudo: say eval(("a","b").Seq.perl ).WHAT
[15:48:13] <p6eval> rakudo 3370f0: OUTPUT«Parcel()»
[15:51:13] <moritz_> cognominal: it's a bug, but a small one. It's
rarely necessary to reproduce the exact list type, as they can all be
coerced very easily (and often automatically)
[15:51:26] <moritz_> rakudo: my $x = (1, 2, 3).Seq; say $x.WHAT
[15:51:31] <p6eval> rakudo 3370f0: OUTPUT«Seq()»
15:53:58] <cognominal> What is the composer for a Seq?
[15:54:08] <moritz_> @list.Seq
[15:54:12] <cognominal> ...if any
Probably a ".Seq" should be appended to the current result returned
by for the Seq .perl method to coerce it to a Seq as it should be.
--
cognominal stef
