On Tue, Sep 15, 2009 at 8:18 PM, yary <not....@gmail.com> wrote:
> Pretty sure you get the 1 as the return value of "say" (same as in
> perl5, print & say return 1 if they were able to output the entire
> string, or 0 if there was an error eg. printing to a closed
> filehandle).
Yeah, I should have been clearer. I was wondering what the 1 was coming from
because I wasn't entirely sure that the lambda's return value should be the
"value" of the capture.
Your later comments about the state of captures makes all of this much
clearer. Thanks.
> And the return value of any block is the last value of
> the block. And you're calling the block because of the () after the
> $x. And I'm pretty sure neither rakudo nor any other perl6
> implementation implements captures very well, and there's still
> discussion about how captures should work.
>
> -y
>
>
>
> On Tue, Sep 15, 2009 at 4:33 PM, Aaron Sherman <a...@ajs.com> wrote:
> > I tried this out, and I'm not 100% certain why I got what I did (#20
> > release):
> >
> > Code:
> >
> > my $x = \(-> { say "Perl 6" }); say $x();
> >
> > Output:
> >
> > Perl 6
> > 1
> >
> > First off, why can I invoke a capture when it contains a lambda?
> Shouldn't I
> > get an error, here?
> >
> > Second, why the 1? Is that the return value of the lambda?
> >
>
