Author: jdlugosz Date: 2009-06-11 02:46:52 +0200 (Thu, 11 Jun 2009) New Revision: 27056
Modified: docs/Perl6/Spec/S03-operators.pod Log: [S03] reword example due to prefix = no longer existing. Presumably the effect still applies if you were to have one, even though it is no longer a built-in operator. Modified: docs/Perl6/Spec/S03-operators.pod =================================================================== --- docs/Perl6/Spec/S03-operators.pod 2009-06-10 08:09:40 UTC (rev 27055) +++ docs/Perl6/Spec/S03-operators.pod 2009-06-11 00:46:52 UTC (rev 27056) @@ -13,8 +13,8 @@ Maintainer: Larry Wall <la...@wall.org> Date: 8 Mar 2004 - Last Modified: 7 Jun 2009 - Version: 167 + Last Modified: 10 Jun 2009 + Version: 168 =head1 Overview @@ -2290,9 +2290,13 @@ The postfix interpretation of an operator may be overridden by use of a quoted method call, which calls the prefix form instead. So C<x().!> is always the postfix operator, but C<x().'!'> will always -call C<!x()>. In particular, you can say things like C<$array.'@'> -and C<$fh.'='>, which will not be confused lexically with C<$fh.=new> -due to the quotes. +call C<!x()>. In particular, you can say things like C<$array.'@'>. +This also includes any operator that would look like something +with a special meaning if used after the method-calling dot. For example, +If you defined a C<prefix:<=> >, and you wanted to write it using +the method-call syntax instead of C<=$object>, the parser would take +C<$object.=> as the mutation syntax (see S12, "Mutating methods). +Writing C<$object.'='> will call your prefix operator. =item *
