[perl #61892] list-comprehension assignments with declaration

[Patrick R. Michaud via RT]

On Thu Jan 01 10:16:14 2009, dave.wh...@gmail.com wrote:
> I've been trying to figure out how to do a "($hd, @tl) = @list"
assignments.
> 
> ./perl6 -e '
>     my @list = 1,2,3;
>     my ($hd, @tl) = @list;
>     say ([$hd], [...@tl]).perl
> '
> [[1], []]

Now working as of 35397:

  $ cat x
  my @list = 1,2,3;
  my ($hd, @t1) = @list;
  say ([$hd], [...@t1]).perl;

  $ ./parrot perl6.pbc x
  [[1], [2, 3]]
  $


I'm pretty sure tests exist for this already, or that this is being
handled by another ticket, so resolving ticket.  Thanks!

Pm