[perl #60620] @a[1].=subst parsefail

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On Mon Nov 17 13:49:03 2008, masak wrote:
> Rakudo r32733:
> 
> <masak> rakudo: my @a; @a[0].=subst( '', '')
> <polyglotbot> OUTPUT[PAST::Compiler can't compile a null node␤current
> instr.:
> [...]
Ah, yes, .= was only handling a scalar on the LHS. Thanks to PAST
enhancements since I first implemented .=, it was nice and easy to
refactor it into something that'd do the right thing...

> my @a = 'abc'; @a[0] .= subst('b','d'); say @a[0]
adc
> my %h = x => 'abc'; %h<x> .= subst('b','d'); say %h<x>
adc

Committed in r33225, plus added tests into assign.t.

Thanks,

Jonathan