Hi there,
question about arrays and array refs in Rakudo today.
I have array ref
my $ar = [1,2,3];
how can I go over it?
I try:
> my $r = [1,2,3]; say $r.elems;
3
> my $r = [1,2,3]; say $r.WHAT;
Array
> my $r = [1,2,3]; "Y".say for $r;
Y
> my $r = [1,2,3]; .say for $r;
1 2 3 #one string
> my $r = <1 2 3>; for $r.list { "Y".say };
Y
> my $r = [1,2,3]; my @a := $r; "Y".say for @a;
Y
Argh! :(((
Any ideas?
Ilya
2008/9/18 Илья <[EMAIL PROTECTED]>:
> Thank you, I try three first too, but do not try :=.
>
> 2008/9/17 Moritz Lenz <[EMAIL PROTECTED]>:
>>
>> Илья wrote:
>>> Hi,
>>> I have some confusion.
>>> I have $arref = [ 1, 2, 3 ];
>>> How I can assign it content to Array today in Rakudo?
>>
>> That's a good question, and I haven't found a simple answer. Here are my
>> attempts so far:
>>
>> > my $a = [1, 2, 3]; my @b = @($a); say @b.elems
>> 1
>> > my $a = [1, 2, 3]; my @b = @$a; say @b.elems
>> Statement not terminated properly at line 1, near "= @$a; say"
>> > my $a = [1, 2, 3]; my @b = list($a); say @b.elems
>> 1
>> > my $a = [1, 2, 3]; my @b = list($a); say @b.elems
>> 1
>> > my $a = [1, 2, 3]; my @b := list($a); say @b.elems
>> 1
>> > my $a = [1, 2, 3]; my @b := $a; say @b.elems
>> 3
>>
>> So the last one seems to succeed, but it's really binding, not
>> assignment, so @b and $a refer to the same variable after that. Change
>> one, and you change the other.
>>
>> Moritz
>>
>> --
>> Moritz Lenz
>> http://moritz.faui2k3.org/ | http://perl-6.de/
>>
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>
