In general, is [op] (p1,p2,p3,p4...)
expected to return the same result as p1 op p2 op p3 op p4... including precedence considerations? That is, should [**](2,3,4) return 2^(3^4)=2^81, or (2^3)^4 = 4096? -- Mark J. Reed <[EMAIL PROTECTED]>
In general, is [op] (p1,p2,p3,p4...)
expected to return the same result as p1 op p2 op p3 op p4... including precedence considerations? That is, should [**](2,3,4) return 2^(3^4)=2^81, or (2^3)^4 = 4096? -- Mark J. Reed <[EMAIL PROTECTED]>