A05 currently says:
The first space in
/[:w foo bar]/
matches \s* before "foo". That's usually what you want,
but if it's not what you want, you have a little problem.
Unfortunately you can't just say:
/[:wfoo bar]/
That won't work because it'll look for the :wfoo modifier.
However, there are several ways to get the effect you want:
/[:w()foo bar]/
/[:w[]foo bar]/
/[:w\bfoo bar]/
/[:w::foo bar]/
I think this was discussed before, but I've lost the reference,
so here's my question: do the parens () and brackets [] have
the same meaning in this context, or is there some difference
between them that I'm overlooking?
Also, it seems sort of odd to me that ":w()" is the same as ":w(1)"
and ":w" here -- I would've expected empty parens to connote
a null, undef, zero, or otherwise false value. Is it generally
true that :xyz() as an adverb will be the same as :xyz(1)...?
(I know that :xyz is the same as :xyz(1), but I'm curious about
:xyz() ).
Pm
