Dave Whipp wrote:
You can use "{time - $epoch}" or "{time.as<%d>}" or "{int time}". (That
last one is not "{+time}", because that would be a floating-point value,
not an integer).
I was thinking: an epoch is just a time, and "int time" is a duration --
the number of seconds since the current epoch. So, the following should
work:
for 1 .. 2 -> {
use epoch time();
sleep 6;
say int time;
}
This should print something close to "6", twice.
But something niggled me: does the value of the RHS of a "use" get
evaluated at run time, or compile time? In perl5, that could definitely
would only execute the C<use> once.
I could see 3 possible behaviors:
1. C<use> sets the epoch for each iteration of the loop, thus calling
time() one per iteration
2. C<use> executes just once, at compile time. Thus seconds iteration
prints approximately "12"
3. C<use> does a compile-time binding of the epoch to the time()
function. So each iteration prints "0".
Which actually happens?
