On 2005-05-17 14:14, "Peter Haworth" <[EMAIL PROTECTED]> wrote:\
>
> Does numbering of captures after an alternation continue as if the
> alternative with the most captures matched?
>
> # $1 $1 $2 $3, even if (a) matched
> rx/ [ (a) | (b) (c) ] (d) /;
I thought that was still like Perl5:
> # $1 $2 $3 $4
> rx/ [ (a) | (b) (c) ] (d) /;
The *numbering* is based on the regex; the *values* are based on the actual
match.
What's changed in the Perl6 design, AIUI, is nested captures. Given this:
> rx/ (a (b (c d) e) f) /
In Perl5, $1 is "abcdef", $2 is "bcde", and $3 is "cd". In the proposed
Perl6 model, there is no $2, just $1 (an object which stringifies to
"abcdef", $1.1 (an object which stringifies to "bcde"), and $1.1.1 (an
object which stringifies to "cd".
>
>
>
> If you explicitly number the first capture in one alternative, does that
> affect the numbering of the other alternatives?
>
> # $4 $4
> rx/ [ $4:=(a) | (b) ] /;
>
>
>> Note that, outside a rule, C<@1> is simply a shorthand for C<@{$1}>
>
> Is @/ also a shorthand for @{$/} ?
>
