Hi, I'm trying to understand the following section in S03:
S03/"Junctive operators" Junctions are specifically unordered. So if you say for all(@foo) {...} it indicates to the compiler that there is no coupling between loop iterations and they can be run in any order or even in parallel. Is this a "for" on a one element list, which happens to be a junction, or does the all() flatten? Is the whole block run once with 1,2 and 3, or does the junction go into the block and autothread each operation? for all(1,2,3) { next if $_ < 2; # testing 1 or all(1,2,3) ? %got{$_} = 1; } say %got.perl; # "(('2', 1), ('3', 1))" or "()" ? The "no coupling" in s03 suggests to me that the right answer is "(('2', 1), ('3', 1))", but I'm just guessing. Brad -- To ask when you already know is politeness. To ask when you don't know is the rule. -- Hagakure http://bereft.net/hagakure/