Ron Blaschke <[EMAIL PROTECTED]> wrote: > I see. Does this morphing work as designed? Creating an array out of > an undef feels somewhat wrong.
Yes and yes ;) A longer answer is: all operators currently need an existing LHS. The canonical way is: lhs = new Undef lhs = a <op> b While we AFAIK don't have ops yet, where an array is created and the morphing to an array is needed, Perl6 hyper operators are just doing that. So the functionality is correct. > I guess the lesson here is: Don't mess with Undef, it's ... undefined. Or for the test case: check the return result of C<dlfunc>. > Ron leo
