Leopold Toetsch <[EMAIL PROTECTED]> wrote:
>>>... . We need some tests, from which size memory is
>>>cleard for malloc and memalign.
Here is a small program, which could be put into a test.
Are there systems out there, without memalign, where malloc.c can not be
linked with?
/*
* test clean memory threshold
*/
#include <stdio.h>
#include <stdlib.h>
#include <malloc.h>
int main(int argc, char *argv[])
{
char *buf;
size_t size;
int j, u;
if (argc != 3) {
printf("usage: test [malloc|memalign] hexsize\n");
return 1;
}
++argv;
size = (size_t)strtoul(argv[1], NULL, 16);
buf = malloc(size);
for (j = 0; j < size; j++)
buf[j] = 0xff;
free(buf);
if (strcmp(*argv, "malloc") == 0) {
printf("malloc\nsize\tclean\tadr\n");
buf = malloc(size);
}
else if (strcmp(*argv, "memalign") == 0) {
printf("memalign\nsize\tclean\tadr\n");
if (size & (size -1 )) {
printf("not a power of 2\n");
return 1;
}
buf = memalign(size, size);
}
else {
printf("usage: test [malloc|memalign] size\n");
return 1;
}
for (j = u = 0; j < size; j++)
if (buf[j]) {
u = 1;
break;
}
printf("0x%x\t%s\t%p\n",
size, u ? "n": "y", buf);
free(buf);
return 0;
}
/*
* Local variables:
* c-indentation-style: bsd
* c-basic-offset: 4
* indent-tabs-mode: nil
* End:
*
* vim: expandtab shiftwidth=4:
*/
leo
