&baz does refer to the Code object itself, as you say.
However, the &bar(...) syntax *will* DWYM too. That's because:
&baz(@args);
is just a shorthand for:
&baz.(@args);
That's not what page 5 of Apoc 6 says:
<quote>
Note that when following a name like "&factorial", parentheses do not automatically mean to make a call to the subroutine. (This Apocalypse contradicts earlier Apocalypses. Guess which one is right...)
$val = &factorial($x); # illegal, must use either $val = factorial($x); # this or $val = &factorial.($x); # maybe this.
In general, don't use the & form when you really want to call something. </quote>
-- Matthijs van Duin -- May the Forth be with you!
