David Whipp wrote: > $b = 7, 6, 5 > @b = 7, 6, 5 I understand that C's *interpretation* of the comma operator will be expunged from Perl 6. But unless comma's *precedence* is also changing, neither of those statements would build a list with three elements.
It seems to me that $b = 7, 6, 5; is the same as ($b = 7), 6, 5; not $b = (7, 6, 5); because '=' binds tighter than ','. So it will assign 7 to $b, and then effectively evaluate the statement 7, 6, 5; which might build a list and then discard it. I.e., it is akin to these statements: [7, 6, 5]; 3 + 4; 7; (and equally feckless). =thom
