Luke Palmer:
# Wait, does this have any meaning?:
# 
#   my &half = \div(y => 2)

Call div() with the named parameter 'y' equal to 2, take a reference to
its return value, and store that in &half.

# Is backslash even a valid operator for reference anymore? If so, this 
# makes sense to me.

I'm sure it's still there.  Otherwise there's no way to take a reference
to a scalar.

--Brent Dax <[EMAIL PROTECTED]>
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