On Thu, Feb 14, 2002 at 02:10:20PM +0000, Dave Mitchell wrote: > 2. If so, how do we distinguish between two PMCs, both of whose > vtable pointers currently point to the 'Dog' vtable, but one of whom has > been delared as type Dog and so should never have it's vatble pointer > updated, and the other which started off as a 'plain' PMC, has temporariky > becomes a Dog by beeing assigned to from a Dog value, but will change > again the next time we assign something to it?
I may be way off here, but why does Parrot need to know its a Dog ? Thats a perl level thing. To Parrot the PMC is an object, Dog would be a property of the value, not the variable. At the Parrot level the difference between my Dog $spot = new Dog; my $scalar = new Dog; is that the prior would have an extra vtable entry to handle assignment. That vtable method only needs to check that what is being assigned is a PMC of the right type. Graham.
