On Fri, Jan 25, 2002 at 06:03:55PM -0800, Larry Wall wrote:
> Do they need to? In the simple case, the hyperoperator provides list
> context to its arguments, but just calls the scalar operation repeatedly
> to fake up the list operation. Any operator
>
> @result = @a ^op @b
>
> is really just something like
>
> @result = for @a; @b -> $a, $b { $a op $b }
Just to make sure I'm not confused, the for loop above should really
look like this:
@result = for @a; @b -> $a; $b { $a op $b }
right? I re-read the Apocalypse and it says that both of these would
be the same, but if that's the case, then I don't understand how you
would take items two at a time across multiple streams.
I expect @a;@b->$a;$b to assign @a[0] to $a, @b[0] to $b, etc.
and @a;@b->$a,$b to assign @a[0] to $a, @a[1] to $b, etc,
-Scott
--
Jonathan Scott Duff
[EMAIL PROTECTED]
