A4 said that there were no barewords in Perl 6. Does this mean that
$foo{bar}
actually should be written
%foo{"bar"}
?
I'm vaguely hoping that the answer is yes, because then we could treat
*all* instances of {...} as a block returning either a closure, a value
for subscripting, or an anonymous hash, rather than having to decide at
tokeniser time.
--
Overall there is a smell of fried onions. (fnord)
