> # > my $foo is const = 0 is true;
> # >
> # > $foo has the property const, while the value 0 in $foo has
> # > the property true.
> #
> # So, if I do
> #
> # my $foo is constant = new Counter(0);
> # $foo->increment # OK
>
> I think so.
Yep. Except the property name is likely to just be C<const>.
> # my $bar = new Counter(0) is constant;
> # $bar->increment; #error
>
> Maybe. I think that would depend on the Counter class's implementation
The "constant" property is applied to the particular reference to the
object that was returned by C<new> and stored in $bar (*not* to the object
itself!) Hence, the C<Counter::increment> method would have to be
something like the following, in order to respect it:
sub increment ($self) {
croak "Can't increment constant Counter" if $self.constant;
}
> # However, if I do
> #
> # %foo is constant = (a=>1, b=>$foo);
> #
> # are only the keys contant; or both the keys and values.
>
> Keys and values, I imagine.
Probably.
Damian
