So Buf is expecting a list of integers. If' you've got one long one in a string like "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78" you want to split it into smaller values so something like this?
my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); Which does the trick I think. On Fri, 10 Jun 2022 at 15:49, ToddAndMargo via perl6-users < perl6-us...@perl.org> wrote: > Hi All, > > I am looking for an easier way to load a buffer. > > I know about this way > > [4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53); > Buf:0x<2A 54 FF 53> > > I would like to do it on one big blast: > > my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78); > Cannot unbox 170 bit wide bigint into native integer > > But do not know the proper syntax. > > Any words of wisdom? Am I stuck with the hard way? > > Many thanks, > -T > -- Simon Proctor Cognoscite aliquid novum cotidie http://www.khanate.co.uk/
