What is happening is that the `start` happens on another thread.
That thread is not the main thread.
The program exits when the main thread is done.
Since the main thread doesn't have anything else to do it exits before that
`sleep` is done.
The more correct way to handle it would be to wait for the `start` to
finish.
my $p = start { sleep 1; say "done" }
say "working";
await $p;
On Tue, Jan 5, 2021 at 7:41 AM Theo van den Heuvel <vdheu...@heuvelhlt.nl>
wrote:
> thanks. That helps.
>
> Elizabeth Mattijsen schreef op 2021-01-05 14:37:
> > If those are the only lines in your program, the program will have
> > exited before the sleep in the start has actually passed. If you
> > change the program to:
> >
> > start { sleep 1; say "done"; exit }
> > say "working";
> > sleep;
> >
> > you should also see the "done".
> >
> >> On 5 Jan 2021, at 14:15, Theo van den Heuvel <vdheu...@heuvelhlt.nl>
> >> wrote:
> >>
> >> Hi gurus,
> >>
> >> The first example in the documentation on the start control flow does
> >> not seem to work as promised.
> >> Here is the code:
> >>
> >> start { sleep 1; say "done" }
> >> say "working";
> >> # working, done
> >>
> >> Both 2020.1 and the 2020.12 version under Ubuntu yield only "working".
> >> Am I missing something?
> >>
> >> --
> >> Theo van den Heuvel
>
> --
> Theo van den Heuvel
> Van den Heuvel HLT Consultancy
>
